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python-study-Tuple

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rhyme = (1,2,3,4,5, "上山打老虎")

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rhyme

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(1, 2, 3, 4, 5, '上山打老虎')

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rhyme[0]

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1

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rhyme[-1]

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'上山打老虎'

不支持修改

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rhyme[1]=10#不支持修改

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---------------------------------------------------------------------------

TypeError                                 Traceback (most recent call last)

~\AppData\Local\Temp\ipykernel_17308\1184099170.py in <module>
----> 1 rhyme[1]=10


TypeError: 'tuple' object does not support item assignment

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rhyme[:3]

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(1, 2, 3)

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rhyme[3:]

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(4, 5, '上山打老虎')

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rhyme[:]

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(1, 2, 3, 4, 5, '上山打老虎')

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rhyme[::2]

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(1, 3, 5)

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rhyme[::-1]

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('上山打老虎', 5, 4, 3, 2, 1)

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nums= (3,1,9,6,8,3,5,3)

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nums.count(3)

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3

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heros=("蜘蛛侠","绿巨人","黑寡妇")

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heros.index("黑寡妇")

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2

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s=(1, 2, 3)

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t=(4,5,6)

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s+t

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(1, 2, 3, 4, 5, 6)

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s*3

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(1, 2, 3, 1, 2, 3, 1, 2, 3)

,用于切割元组

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w=s, t

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w

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((1, 2, 3), (4, 5, 6))

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for each in s:
    print(each)

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2
3

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for i in w:
    for each in i:
        print(each)

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4
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6
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5
6

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s=(1,2,3,4,5)

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[each*2 for each in s]

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[2, 4, 6, 8, 10]

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(each*2 for each in s) #生成器

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<generator object <genexpr> at 0x00000241A7CCF200>

没有元组推导式

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x=(520)

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x

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520

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type(x)

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int

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x = (520,)

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x

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(520,)

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type(x)

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tuple

打包和解包

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t=(123,"FishC",3.14)

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t

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(123, 'FishC', 3.14)

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x, y, z = t

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x

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123

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y

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'FishC'

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z

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3.14

both applyed to list and tuple

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t=[123,"FishC",3.14]

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x, y, z = t

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x

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123

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y

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'FishC'

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z

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3.14

左右变量数量一致

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a, b, *c="FishC"

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a

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'F'

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b

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'i'

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c

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['s', 'h', 'C']

多重赋值

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x, y = 10, 20

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x

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10

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y

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20

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_=(10,20)

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x, y = _

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x

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10

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y

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20

security

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s=[1,2,3]

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t=[4,5,6]

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w=(s,t)

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w

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([1, 2, 3], [4, 5, 6])

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w[0][0]=0

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w

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([0, 2, 3], [4, 5, 6])

此时对于元组中可变的列表，依然可以更改

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